Formula of Slope

[msamadov]

Hi,

I'm a NT newbie and trying to create a simple formula for calculating the slope value of the Highest Highs.

What I can't figure, however, is how I can extract the number of bar. With the HighestBar() method I can get the number of bars within the lookback period, but how can I get the number of bars ago for the period preceding the current one?

Below is the formula (currently not working) for what I am trying to do:

Slope1= Slope((MAX(High,ratio)[0]-MAX(High,ratio)[ratio]),1,0);

here's I am calculating the Highest High for the current period (say, 5 bars - from 0 to 4th) and the HH for the period from 5th to 9th.

Generally speaking, what is there universal method for getting time stamp or # of bars ago for given event?

Thanks!

[NinjaTrader_Josh]

msamadov,

You need to store your calculations into a DataSeries before you can run Slope() on it. Please see this article: http://www.ninjatrader-support.com/H...taSeriesObject

To get the timestamp of your bars just use Time[0] where 0 is the index of the bar you want the timestamp of.

[geeknick]

How to Find the Slope of a LineBack to Top
Determine the slope of a line, which contains the points A (-1, -2), B (-2, 1):

Solution:

Here, x1 = -1, x2 = -2, y1 = -2, y2 = 1.

Slope of the line, m = [ (y2 - y1)/(x2 - x1)]

= [(1 + 2)/(-2 + 1)]

= [3/(-1)]

Slope of the line (m) = -3


The slope formula of the line is:

Slope (m) = [ (y2 - y1)/(x2 - x1)]



Slope (m) =Rise / Run

(Rise = change in the y co-ordinate; Run = change in the x co-ordinate)

In the above given graph, the Rise is given for the points B (4,2) and C (4,4) and the Run is given for the points A (2,2) and B (4,2)

Rise = change in the y - coordinate = 4-2 =2

Run = change in the x- coordinate = 4-2 =2

Using the slope formula, we get :

Slope( m ) = Rise / Run = 2 / 2 =1